Check Even or Odd - easyhaicode.com

Check Even or Odd Number

Problem Statement

Write a program to check whether a given number is Even or Odd.

A number is:

Even if it is divisible by 2
Odd if it is not divisible by 2

This is one of the most common beginner and interview questions.

Explanation

To determine whether a number is even or odd:

Use the modulus operator (%)
If number % 2 == 0, the number is Even
Otherwise, the number is Odd

Example

If the input number is 10:

If the input number is 7:

🔍 Approach

Read an integer N
Check N % 2
Print Even or Odd based on the result


#include <stdio.h>

int main() {
    int n;
    scanf("%d", &n);

    if(n % 2 == 0)
        printf("Even");
    else
        printf("Odd");

    return 0;
}


#include <iostream>
using namespace std;

int main() {
    int n;
    cin >> n;

    if(n % 2 == 0)
        cout << "Even";
    else
        cout << "Odd";

    return 0;
}


import java.util.Scanner;

public class EvenOdd {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();

        if(n % 2 == 0)
            System.out.print("Even");
        else
            System.out.print("Odd");
    }
}


n = int(input())

if n % 2 == 0:
    print("Even")
else:
    print("Odd")

Input

Output


Even

⏱️ Time and Space Complexity

Time Complexity: O(1)
Space Complexity: O(1)

💡 Tips for Beginners

% operator is used to find remainder
Even numbers always have remainder 0 when divided by 2
This logic works for positive and negative numbers
Try extending this program to check divisibility by 3 or 5

Conclusion

The Check Even or Odd program is a fundamental problem that helps beginners understand conditions, operators, and decision making. Mastering this logic is essential before moving on to more complex programs involving conditions and loops.

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Happy Coding 😊